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(x)=4x^2+3
We move all terms to the left:
(x)-(4x^2+3)=0
We get rid of parentheses
-4x^2+x-3=0
a = -4; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-4)·(-3)
Δ = -47
Delta is less than zero, so there is no solution for the equation
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